Suppose p(a) = 0.76, p(b/a)= 0.30 and p(b/a bar)= 0.02. Find p(a and b), and p(a bar and b). use these to construct a probability table. Now use the table to find the following.

a) p(b bar/ a)
b) p( b bar/ a bar)
c) p(b)
d) p( b bar)
e) p( a / b)
f) p( a bar/ b)
g) p( a/ b bar)
h) p( a bar/ b bar)

Question

Suppose p(a) = 0.76, p(b/a)= 0.30 and p(b/a bar)= 0.02. Find p(a and b), and p(a bar and b). use these to construct a probability table. Now use the table to find the following.

a) p(b bar/ a)
b) p( b bar/ a bar)
c) p(b)
d) p( b bar)
e) p( a / b)
f) p( a bar/ b)
g) p( a/ b bar)
h) p( a bar/ b bar)

triciaal · Answer

is your bar the same as prime,  (for the event not happening)?

triciaal · Answer

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