Question

Find the angle between the given vectors to the nearest tenth of a degree.

u = <2, -4>, v = <3, -8>

A) 3.0°
B) 6.0°
C) -7.0°
D) 16.0°

Answer 1

@pooja195 @Mehek14 @TheSmartOne

Answer 2

\[u \cdot v = \left| \left| u \right| \right|\left| \left| v \right| \right|\cos \Theta\]

Answer 3

so u = (2*3) and v= (-4(-8)= 6+32=38
||u||= sqrt(2^2 + 3^2)
||v|| = sqrt((-4)^2 + (-8)^2

so
38/(sqrt(2^2 + 3^2))(sqrt((-4^2) + (-8)^2) = COS(THETA)

Answer 4

theta = 38/(sqrt(2^2 + 3^2))(sqrt((-4^2) + (-8)^2)