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Express cos7mcos3m as a sum or difference
Answer choices: 1/2cos2m + 1/2cos5m 1/2cos4m - 1/2cos10m 1/2cos10m - 1/2cos4m 1/2cos4m + 1/2cos10m
I think it's either B or D.
\[\large\rm \cos A \cos B=\frac12\left[\cos(A+B)+\cos(A-B)\right]\] Just plug the stuff into the formula :O
So ya it's uhhh... one of these 4 options +_+
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I don't fully understand. Can somebody help?
Your question is cos(7m)cos(4m) Use the formula Zepdrix gave you :) You plug in 7m for A and 4m for B and them simplify, and finally distribute the 1/2 (:
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