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Parabola question, check my answers?
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y^2 + 6y - 2x + 13 = 0
Vertex: (2, -3) Focus: (2.5, -3) Directrix: x = 1.5 Length of Focal Chord: 1/2 ^Does all of this look right?
lets check
thanks :)
seems good http://www.wolframalpha.com/input/?i=parabola+y%5E2+%2B+6y+-+2x+%2B+13+%3D+0
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Thanks! Even the focal length? that's what I was most unsure about
And I don't see it on there... unless the length of the focal chord is the same thing as the focal parameter? In which case I'd be wrong.. somehow...
the focal length is the distance between the vertex and the focus right?
I believe so, not positive
pretty sure that is what it is, so your answer is correct
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Okay, thanks!
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