Question

2a^2-3a-2=0
please show the steps

Answer 1

Here's a solution using the quadratic equation:
x = -b +-square root (b^2 -4ac) / 2a

a=2 b=-3 c=-2
x = [--3 +-sq root(9 -4*2*-2)]/2*2
x = 3 +-sq root (9 +16) / 4
x1 = (3 + 5) / 4
x1 = 2

x2= (3-5) / 4
x2 = -2 / 4
x2 = -.5

Answer 2

2 a^2 - 3 a - 2 = 0
(a-2) (2 a+1) = 0
a=-(1/2), a=2