Question

(2^8 ⋅ 3^−5 ⋅ 6^0)^−2 ⋅ (3^-2/2^3)^4 ⋅ 2^28 Find the value of the following expression,Write your answer in simplified form. Show all of your steps.

Answer 1

i know the answer to the problem i just don't know how to explain how i solved it

Answer 2

Distribute the exponents inside the parentheses. Show your work.

Answer 3

in math when it asks you to explain something, just list the steps of how you got it, or as you do it write it down.

Answer 4

guys please help

Answer 5

any idea what 6^0 equals ?

Answer 6

nope, either 6 or 0

Answer 7

1. Anything ^0 = 1.

Answer 8

we could brute force this (a calculator can tell you the answer)
but we can also use this rule
\[ ( a^x b^y )^z = a^{xz} b^{yz}\]

Answer 9

on this
\[ (2^8 ⋅ 3^{−5} ⋅ 6^0)^{−2} \]

Answer 10

care to try applying that "rule" ?