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inverse tangent sqrt3/3
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\[\tan^{-1} \frac{ \sqrt{3} }{ 3 }\] How?
\[\frac{ \sqrt{3} }{ 3 } = \frac{ 1 }{ \sqrt{3} }\]
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***How?*** in general, you use a calculator. However, there are some angles that people memorize the sine , cosine and tangent they are 0º, 30º, 45º, 60º and 90º see http://www.analyzemath.com/trigonometry/special_angles.html in your problem, you have one of these "special" angles
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