Question

a boy walks to his school at a dist of 6 km at a constant speed of 2.5kmhr and returns home on the same path at a constant speed of 4 kmhr ...find avg vel

Answer 1

your work?

Answer 2

total dist = 12
constant speed = 2.5+4 = 6.5

12/6.5 = 120/65 = 24/13

Answer 3

is answer 0 ?

Answer 4

its 40/13..but how?

Answer 5

bhai displacement toh zero hoga na

Answer 6

avg velocity poochi h

Answer 7

that i know....

Answer 8

phir answer 0 hona chahiye na

Answer 9

aur avg speed kya hogi?

Answer 10

\[\large \bf avg~speed=\frac{total~distance}{total~time~taken}\]

Answer 11

time nahi diya h...

Answer 12

time=distance/speed

Answer 13

\[\large \bf =\frac{6+6}{\frac{6}{2.5}+\frac{6}{4}}\]

Answer 14

solve kr le

Answer 15

solve karta hon..let me frame d egn..