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If BC=8 and DC=4, what is the radius?http://www.intervisualtechnology.us/data/1/9050/apply_12_1.png
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note the radius an x and use pythagora"s bc. there is a right triangle so you can calculi it easy in this way
AC = 4+x
AB = x BC=8
using pythagora"s you can writing (x+4)^2 = 64 +x^2 do you can continue it now ?
x^2 +8x +16 = 64 +x^2 solve it for x
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8x=48 x = ?
divide both sides by 8 what will get for x ?
x=6
exactly do you understand it now ?
hope helped bye bye
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thank u
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