Question

I need help.. @phi or anyone else who is good wilth algebra 1.. Its an honors assignment.

Answer 1

@pooja195 , look at this http://prntscr.com/bvalx7 Task 1.

Answer 2

@Jadeishere @Hero @Data_Lg2 @sammixboo @pooja195

Answer 3

@OswaldMurphy are you still there?

Let's start with \(\sf Task 1\)

First, assign any values for a, b, c, and d. Can you do that?
a=
b=
c=
d=

Answer 4

Yes, I think I got it.

Answer 5

would you mind telling me what you have done so far? (:

Answer 6

Part 1 is f(x) = (x – 2)/4
g(x) = 4x + 2

Answer 7

Part 2 is, y = (x - 2)/4. We find the inverse so, x = (y - 2)/4. Multiply by 4, 4x = y - 2. Add 2, y = 4x + 2. Ill brb, ok?

Answer 8

y = cx - 2 = y = cx - 3 because of inverse.

Answer 9

@Data_Lg2 @Jadeishere @ganeshie8

Answer 10

I got this,
Part 1).
f(x) = (x – 2)/4
g(x) = 4x + 2

Part 2).
y = (x - 2)/4. We find the inverse so, x = (y - 2)/4. Multiply by 4, 4x = y - 2. Add 2, y = 4x + 2.
y = cx - 2 = y = cx - 3 because of inverse.

Answer 11

Sorry I had to refresh.
So far you are going great.

y = (x - 2)/4.
Switching x & y variables: x = (y - 2)/4.
Multiply by 4: 4x = y - 2
Add 2 on both sides: y = 4x + 2. ---> this function equals the function g(x)


For part 3: You just replace the 'x' variable of the function g(x) with the function f(x) and then evaluate.

\(\sf \Large g(f(x)) = 4( \color{red}{\frac{x-2}{4}})+2\)

Answer 12

tell me what you will get..

Answer 13

How do i solve that 0-0

Answer 14

you just simplify it.

Do this part first, what will you end up with?
\(\sf \Large 4( \color{red}{\frac{x-2}{4}})\)

Answer 15

x-2..

Answer 16

right, now you have

\(\sf \Large g(f(x)) = \color{red}{x-2}+2\)

simplify it more and you will get...?

Answer 17

Sorry I got suspended -_-

Answer 18

:O g(f(x)) = x OMG

Answer 19

yep, you got it.

Answer 20

I gtg, I think you can manage to do Part 4 now (:

For task 2, try opening a new thread so that others can help you. Sorry, I have to go somewhere rn..