Question

If Tan A -Tan B =x and Cot B - Cot A=y;
Prove that:Cot (A-B)=1/x + 1/y

Answer 1

Try this: cot(A-B) = 1/tan(A-B) and continue fro there.

Answer 2

Give full solution

Answer 3

From the Open Study Code of Conduct ( http://openstudy.com/code-of-conduct):

OpenStudy values the Learning process - not the ‘Give you an answer’ process.
@Bhuvan, most people will help you if you show that you are helping with your own learning. Most people won't just hand you answers.

Answer 4

Recall tan(A-B) can be expanded

\[LHS = \cot(A-B) = \frac{ 1 }{ \tan(A-B) } = \frac{ 1 }{ \frac{ \tan A - \tan B }{ 1+\tan A \tan B } }=\frac{ 1+\tan A \tan B }{ \tan A-\tan B }\]

Then you sub in x and y into RHS 1/x and 1/y and compare.

Answer 5

"Give full solution" lol