Question

Quantum # Practice.
A. When n=3, L (caps to minimize confusion) can have values of:
for 3d orbital L has value of:

B. When n=4, L can have values of:
For 4p orbital, L has value of:

***
Check my answers please!
The principal quantum # n can have the values (1-7)
The angular momentum quantum # L can have integer values from (0 to n-1)
The magnetic quantum # m can have integer values from (-L to L)

Answer 1

\(l=n-1\geq 0\)

s corresponds to \(l=0\)
p corresponds to \(l=1\)
d corresponds to \(l=2\)
f corresponds to \(l=3\)

Answer 2

I put "when n=3 then L= -3,-2,-1,0,1,2,3" ?

Answer 3

nope, \(m_l=\pm l\)

however \(l\) can't be negative

Answer 4

oh right... woops

Answer 5

n=3 then ... 0, 1, 2 for L

Answer 6

and then if it's 3d then I get L=2

Answer 7

so the values you wrote are incorrect.

for n=3, \(l\) can be 2, 1, or 0

and say for \(l=2\), then \(m_l=-2,-1,0,+1,+2\)

Answer 8

"and then if it's 3d then I get L=2" yes this is right.

Answer 9

okay thank you

Answer 10

no problem

Answer 11

so basically L is everything from 0 to "n-1"?

Answer 12

Yeah, those are possible values when only the principal number is specified

Answer 13

okay

Answer 14

how do I calculate whether s is \(\pm\) though?

Answer 15

s orbital can't be negative

Answer 16

s,p,d,f,s.... they are never negative

Answer 17

I meant s quantum # oops sorry

Answer 18

O.o

Answer 19

wym ?

Answer 20

spin quantum

Answer 21

oh

Answer 22

there are two values of `s quantum` +1/2 and -1/2
+1/2 for clockwise direction
-1/2 for anti clockwise direction

Answer 23

yes but how to calculate

Answer 24

well we can't calculate it

Answer 25

it's obvious that we have +1/2 and -1/2

Answer 26

hey,tell me what is the full question?
we'll discuss it

Answer 27

it is more concepts than questions right now...

Answer 28

s orbitals are non directional