Question

Topic: Limits - Continuity

To two decimal places, find the value of k that will make the function continuous everywhere.

Answer 1

SOLUTION:

3(3)+k = 3^2k-6
9+k = 9k-6
15 = 8k

k=0.53

Answer 2

Please tell me if I made an error.

Answer 3

that looks ok until
8k= 15
divide both sides by 8
k= 15/8

Answer 4

OHHHHHHHHHHH thank you!!!!