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Mathematics 19 Online
OpenStudy (javyb13):

NEED HELP ON QUIZ what are the vertex focus and directrix of the parabola with the given equation y=1/28(x-4)^2-5 a)vertex:(4,-5);focus:(4,-12);directrix:y=2 b)vertex:(-4,-5);focus:(4,2);directrix:y=2 c)vertex:(-4,-5);focus:(4,-12);directrix:y=-12 d)vertex:(4,-5);focus:(4,2);directrix:y=-12

OpenStudy (peachesncream8):

\[Y=\frac{ 1 }{28 }(x-4)^2-5\]

OpenStudy (peachesncream8):

so that means that your centeror vertex is (4,-5) and eliminate b and c

OpenStudy (peachesncream8):

The equation is so divide the 1/28 by 4 to get your p value....

OpenStudy (peachesncream8):

the p value tells you to go up -p away from the vertex and +p from the vertex to reach your directrix and focus

OpenStudy (javyb13):

thank you!

OpenStudy (peachesncream8):

yup no problem

OpenStudy (peachesncream8):

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