where the code for 1000th prime no. goes for infinite loop
counter=3
n=6
while counter!=1000:
n+=1
for c in range(2,n-1):
if(n%c==0):
counter+=1
print('1000th prime number is '+n)

Question

where the code for 1000th prime no. goes for infinite loop
counter=3
n=6
while counter!=1000:
	n+=1
	for c in range(2,n-1):
		if(n%c==0):
			counter+=1
print('1000th prime number is '+n)

p0sitr0n · Answer

set n=1 and counter=1

sudhansharma · Answer

it's still coming out to be an infinite loop.

kmd284 · Answer

thats because your counter variable passes 1000 when inside the for loop which means it will never equal 1000 when the while loop tests the condition.

kmd284 · Answer

you need to ensure that it doesn't increment count till the very last iteration and only if nothing before it divided evenly into n