Ask your own question, for FREE!
Mathematics 7 Online
OpenStudy (tammyd):

Kayla has a bowl of beads that contains 42 yellow beads, 28 green beads, 12 white beads, and 18 red beads. She randomly draws a bead from the bowl.

OpenStudy (tammyd):

someone please help

OpenStudy (tammyd):

The probability of Kayla not drawing a yellow or a green bead is %. The probability of Kayla drawing a red or a green bead is %.

OpenStudy (evoker):

For one bead fairly easy, add up the type you want and divide by the total number of beads

OpenStudy (sila1453):

The probability of Kayla not drawing a yellow or a green bead is 70 %. The probability of Kayla drawing a red or a green bead is 46 %. ....

OpenStudy (evoker):

Looks like you have 100 beads in this case, so for the first add all of the cases that aren't yellow or green and divide by 100

OpenStudy (evoker):

Sila is right on the second, but for the first is says not drawing and sila did they do draw.

OpenStudy (tammyd):

thank you both so much. and so I add the white bread and the red bread and divide by 100?

OpenStudy (tammyd):

beads*

OpenStudy (tammyd):

@Evoker

OpenStudy (tammyd):

I should get 0.3?

OpenStudy (welshfella):

@Sila1453 PLease dont give direct answers . Read the Code of Conduct.

OpenStudy (evoker):

Well that is the answer in decimal if you want a percent multiply by 100

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!