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Mathematics 8 Online
OpenStudy (dillonmerv):

The surface area of a right-circular cone of radius r and height h is S=πr(sqrt(r^2+h^2)), and its volume is V= 1/3πr^2h. What is the ratio h/r for a cone with given volume V=3 and minimal surface area S? (h/r)=

OpenStudy (evoker):

Hmm, I think you want to use the volume equation to find an equation between h and r, and then substitute into S and find where the derivative is 0 to find the extrema.

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