In the diagram, the equation of RQ is y=2x-1. If QP is parallel to x-axis and the coordinates of P are (8,4), then find the distance from P to Q
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OpenStudy (sugarmochi):
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OpenStudy (welshfella):
the equation of the line QP is y = 4 beacuse it is horizontal and pass through y = 4
To find the x coordinate of Q you solve the system of equations
y = 2x - 1
y = 4
OpenStudy (welshfella):
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OpenStudy (sugarmochi):
Then would you sub y with 4?
So the equation would be 4=2x-1 ?
OpenStudy (welshfella):
yes
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OpenStudy (sugarmochi):
x= 2/5
OpenStudy (welshfella):
not quite
its the inverse of that
2x = 4 + 1 = 5
x = 5/2 or 2.5
OpenStudy (sugarmochi):
oh- sorry my bad. Accidentally wrote it the wrong way..whoops-
OpenStudy (welshfella):
the coordinates of Q are (2.5,8) and of P are (4,8)
so now it is easy to find the distance between P and P
Just subtract the x-coordinates.
OpenStudy (sugarmochi):
1.5?
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OpenStudy (welshfella):
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OpenStudy (welshfella):
sorry i confused you P is (8,4) not (4,8). My typo.
OpenStudy (welshfella):
QP = 8 - 2.5
OpenStudy (sugarmochi):
5.5 !
OpenStudy (welshfella):
yes
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OpenStudy (welshfella):
another typo Q is (2.5,4) but it didnt make any difference to calculation.
5.5 is correct
OpenStudy (sugarmochi):
thankyou !!
OpenStudy (sugarmochi):
Oh- uhm if you're still here and all, is it possible for you to help me with another question?