Question

In the diagram, the equation of RQ is y=2x-1. If QP is parallel to x-axis and the coordinates of P are (8,4), then find the distance from P to Q

Answer 1

the equation of the line QP is y = 4 beacuse it is horizontal and pass through y = 4
To find the x coordinate of Q you solve the system of equations
y = 2x - 1
y = 4

Answer 2

Then would you sub y with 4?
So the equation would be 4=2x-1 ?

Answer 3

yes

Answer 4

x= 2/5

Answer 5

not quite
its the inverse of that
2x = 4 + 1 = 5

x = 5/2 or 2.5

Answer 6

oh- sorry my bad. Accidentally wrote it the wrong way..whoops-

Answer 7

the coordinates of Q are (2.5,8) and of P are (4,8)

so now it is easy to find the distance between P and P
Just subtract the x-coordinates.

Answer 8

1.5?

Answer 9

sorry i confused you P is (8,4) not (4,8). My typo.

Answer 10

QP = 8 - 2.5

Answer 11

5.5 !

Answer 12

yes

Answer 13

another typo Q is (2.5,4) but it didnt make any difference to calculation.

5.5 is correct

Answer 14

thankyou !!

Answer 15

Oh- uhm if you're still here and all, is it possible for you to help me with another question?

Answer 16

i have to go out for 1 hour