Given: F(x) = 2x - 1; G(x) = 3x + 2; H(x) = x 2 Find F[G(x)] - F(x).
Answer choices are 4x+4 4x+2 4x
@jhonyy9
check it please there given again H(x) too but you dont wrote again used it i think you missed it from there yes ?
F(x) = 2x - 1; G(x) = 3x + 2; H(x) = x^2
yes i understand it but on the find case there missed the H(x) where you need use it ?
Oh I do not think you do. The find case is F[G(x)] - F(x)
Is the question incorrect? Or can we ignore the H?
but than you need finding just this F(G(x)) -F(x) so why was given H(x) ?
I do not know. Here is an image of the question.
ok. so than you are sure i accept it so
I am sure.
ok i see it now but i think there is wrote wrong the last F(x) need being H(x) my opinion
I see. What you are saying does make sense. So if we do it without H will be get an available answer?
common please try it so how wrote there and we will see what will result - ok. ?
okay
so f(x) = 2x-1 g(x) = 3x+2 f(g(x)) = ?
using what i explained you before
I got 4x+4
just substitute the g(x) in place of x inside equation of f(x) right ?
i think not is right please write me here step by step
Oh no I mean for that i got 5x
so 3x+2(x) = 5x
f(x) = 2x-1 g(x) = 3x+2 f(g(x)) = f(3x+2) = ?
in place of x substitute the 3x+2
f(x) = 2x-1 f(3x+2) = 2(3x+2) -1 = ?
so it would be 6x+3
yes exactly - this is easy - yes ?
yes is that the answer?
or more steps?
yes
okay :)
6x+3 so you can factorizing out the 3 and will get 3(2x+1)
this is the answer how is wrote there but i think there missed anything
this H(x) need used
oh so thatt means the question is incorrect right?
exactly
okay thank you a bunch!
do you have again ? and now do you understand it sure right ?
Yes I am done. I understand. Thank you.
excouzme what mean this bunch ? bc i dont meet it till today
or this is just a slent used by students ?
sorry but i m from Europe and i learned alone English from books and internet and i dont know again this word of bunch ?
can you explain it me please
ty
bunch = much
ok. was my pleasure and than you wan,like anytime than i m here online just tag me there and i will try help you good luck bye bye
or do you wan we trying it with the last term to be H(x) ? probably in this way we will get an answer from given choices
Diamond are you here please ?
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