Question

If sin Θ = negative square root 3 over 2 and π < Θ < 3 pi over 2, what are the values of cos Θ and tan Θ?

Answer 1

\[\sin \theta=-\frac{ \sqrt{3} }{ 2 }=-\sin \frac{ \pi }{ 3 }=\sin \left( \pi+\frac{ \pi }{ 3 } \right)=\sin \frac{ 4 \pi }{ 3 }\]
\[\theta=?\]
then find cos thete and tan theta

Answer 2

i don't get what you mean find cos theta

Answer 3

would cos be -1/2

Answer 4

tan= sq rt of 3

Answer 5

\[\theta=\frac{ 4 \pi }{ 3 }\]
\[\cos \theta=\cos \frac{ 4 \pi }{ 3 }=\cos \left( \pi+\frac{ \pi }{ 3 } \right)=-\cos \frac{ \pi }{ 3 }=?\]

Answer 6

are my answers right?

Answer 7

yes