Question

help with average rate question plz?

Answer 1

#4: http://www.houstonisd.org/cms/lib2/TX01001591/Centricity/Domain/4747/M2%20Average%20Rate%20of%20Change%20vs.%20Instantaneous%20Rate%20of%20Change.pdf

Answer 2

#4 -- slope of line is miles per minute which is speed, the avg speed of Susan should be equal to Jonathon because the slopes are equal
use slope formula to compute Susans avg slope:
\[\frac{y_2 - y_1}{x_2 - x_1} = \frac{14 - \frac{7}{3}}{20-0} = \frac{\frac{35}{3}}{20} = \frac{35}{60}\]
Notice this is equal to 35 miles per hour

Answer 3

#5 ---- Susan drives faster than 35 mph if the slope is greater than avg slope
Find point on graph where slope is "steeper" than line connecting the 2 endpoints

Answer 4

#6 --- same as above, Find points where slope is exactly the same as avg slope