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Your original question was a fraction but your reply is a matrix. Can it be assumed you want to simplify the fraction?
yeah sorry
\[\frac{ 1-\cos^2x }{ sinx }=\frac{ \sin^2x }{ sinx }=\sin x\]
Pythagorean identity: \[\sin^2x+\cos^2x=1\]
Difference of 2 squares = sum x difference i.e. \[(a^2-b^2)=(a+b)(a-b)\]
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