Question

Question in comments

Answer 1

@agent0smith is this correct?

Answer 2

the first stuff under the radical is x+5

that must be positive or zero. What do you get when you solve \(\Large x+5 \ge 0\) for x?

Answer 3

x> or = -5

Answer 4

yes correct

Answer 5

the other stuff under the other square root must be positive. It cannot be zero due to a division by zero error.

solve for x
1-x > 0
tell me what you get

Answer 6

x < or = 1 but that isn't an option

Answer 7

no just x < 1

there is no "or equal to" part in this piece

Answer 8

Oh ok I get it now thank you!

Answer 9

so you found out that \(\Large x \ge -5\) AND \(\Large x < 1\)

Answer 10

which is equivalent of saying \(\Large -5 \le x\) AND \(\Large x < 1\)

Answer 11

Yep so the end result is −5≤x<1

Answer 12

correct