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use the properties of logarithms to evaluate the following
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\[\log_{2}2^5 \]
Ooohhh, this is an easy one! This is the rule \(\Large log_x x^y = y\) Because basically \(\Large log_x x^y = y~log_x x = y(1) = y\)
so is it 5?
Correct! :D
oh wow the explanation on my paper makes it seam so difficult!
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thanks again idk what i' do without you XD
Anytime! :D
I don't know about you... but I know what I would do without you. Sleep! XD
ahahaha then go to bed I can manage (hopefully)
sure, have fun with math! :)
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thanks I shall :D
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