help!
\[-7x^2y^2 (8x^2y -5xy +11xy^2 -31)\]
@TheSmartOne
You'll need to distribute a(b - c) = ab - ac You'll apply the distributive property to your question. It would be something like this: a(b - c + d - f) = ab - ac + ad - af
can u explain it to me in numbers... thats really confusing for me
@sleepyjess @imqwerty
I did it with variables, mhmm 5(1 - 5 + 3 + 6) we can simplify the parenthesis, but in your question we can't since they aren't like terms, so let's not simplify the parenthesis 5(1) - 5(5) + 5(5) + 5(6) = 5 - 25 + 25 + 30 = 5 + 30 = 35
i dont understand with the random numbers sorry... I know I have to distribute the \[-7x^2y^2\] to all the numbers in the parentheses.. for the first one i got
yes, you multiply it with each term in the parenthesis
\[-42x^4y^2\]
I'm having trouble with the next one
what is -7 * 8 = ? and y^2 * y = ? you got x^4 correctly :) then we'll move to the next part :)
oh I'm meant 56
idk what y^2 * y = ? would be
use the property: \(\Large a^b \times a^c = a^{b+c}\)
y^3
i need help with the next part
\(-7x^2y^2 (8x^2y -5xy +11xy^2 -31)\) Now we need to do -7x^2y^2 * -5xy what do you get? :)
i dont know.. i need help...i think maybe -35x^3y^3
mhmm, not quite what is -7 * -5 = ? negative times negative equals positive :P
35x^3y^3
so far we have \(-56x^4y^3 + 35x^3y^3\) we still need to find -7x^2y^2 * 11xy^2 and -7x^2y^2 * -31
-77x^3y^4
yes, and -7x^2y^2 * -31 = ?
217x^2y^2
so our final answer is \(-56x^4y^3 + 35x^3y^3 -77x^3y^4+ 217x^2y^2\)
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