Question

help please

find the area of the region . Decide whether to integrate with respect to x or y . Draw a typical approx rectangle and label the height and width.

Answer 1

\[y= x^2-4x\]
\[y=2x\]

Answer 2

okay so i set them equal to each other in order to solve for x so how do i know if i would integrate from x or y ?


\[x^2-4x-2x=0\]

\[x^2-6x=0\]

\[x=0 and x=6\]

Answer 3

\[y=x^2-4x+4-4\]
\[y+4=\left( x-2 \right)^2\]
it is an upward parabola with vertex (2,-4)