Question

X^2-2x-15 X-5
___________ / _________
X-3 X^2-9

Answer 1

Hello Ms Raylynn!\[\large\rm \frac{x^2-2x-15}{x-3}\div\frac{x-5}{x^2-9}\]Recall your `keep change flip rule` or however you've learned it.
\[\large\rm \frac{a}{b}\div\frac{c}{d}\quad=\quad \frac{a}{b}\times\frac{d}{c}\]When we divide by a fraction,
we can rewrite it as multiplication of the flip of that second fraction.
~Keep the first fraction the same.
~Change the operation from division to multiplication.
~Flip the second fraction.

Do you understand how we can apply this rule to our problem?

Answer 2

so after used these above wrote by @zepdrix you will can factorizing

x^2 -2x -15 = (x-5)(x+3) and x^2 -9=(x-3)(x+3)
so after these you will can simplify it easy
hope these helped