Question

4sinx=-cos^2x+1

Need help please, I don't understand.

Answer 1

What are you trying to solve?

Answer 2

Trying to solve for x

Answer 3

\[4\sin x+\cos ^2x-1=0\]
\[4\sin x+(1-\sin ^2x)-1=0\]
\[-\sin ^2x+4\sin x=0,\-sin x(\sin x-4)=0 \]
sin x=0,
\[x=?\]
\[\sin x=4 (rejected)~as ~\left| \sin x \right| \leq 1\]