Question

Pre Cal/Calculus/Trig Question

Answer 1

\[\cos(\sin ^{-1}(2x))\]

Answer 2

This is another problem i need help with \[ \sec(Arctan(4x))\]

Answer 3

Hey :)
Welcome to OpenStudy!\[\large\rm \cos\left[\color{orangered}{\sin ^{-1}(2x)}\right]\]It might be helpful to label this inner part as something, an angle,\[\large\rm \color{orangered}{\sin^{-1}(2x)=\theta}\]

Answer 4

We can relate this to the sine function,
taking inverse, ya?\[\large\rm \sin \theta=2x\]

Answer 5

mhm

Answer 6

Let's draw a triangle to illustrate this relationship.

Answer 7

Hmm so we recall that sine is defined as `opposite` by `hypotenuse`, ya?