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Mathematics 20 Online
OpenStudy (canada907cat):

Use a table to estimate limx->3 (x^3-3x^2+6-2x)/x-3. I know the middle value is three but I dont know what the other value would be.

OpenStudy (canada907cat):

|dw:1471988118949:dw|

OpenStudy (zzr0ck3r):

put in the x values and look at the y values, they will all be really close to a number, that number is your answer.

OpenStudy (zzr0ck3r):

Did it say "use a table" or "use the table"?

OpenStudy (zzr0ck3r):

nm i see. Ok just plug in numbers close to 3.

OpenStudy (canada907cat):

so would it be like 2.997, 2.998, 2.999, 3, 3.001, 3.002, 3.003?

OpenStudy (zzr0ck3r):

exactly

OpenStudy (canada907cat):

oh yay, I got something right!

OpenStudy (zzr0ck3r):

The answers you get out will be very close to some number

OpenStudy (zzr0ck3r):

what is that number?

OpenStudy (canada907cat):

hold on I entered it wrong in my calculator give me a second.

OpenStudy (canada907cat):

im guessing 7?

OpenStudy (zzr0ck3r):

yep

OpenStudy (zzr0ck3r):

Learn to use this site to check your answers https://www.wolframalpha.com/input/?i=lim((x%5E3-3x%5E2%2B6-2x)%2F(x-3),x,3)

OpenStudy (canada907cat):

oh cool well thank you for clarifying that for me. I really do appreciate it. Also, thank you for the website suggestion.

OpenStudy (zzr0ck3r):

no problem

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