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Find the sum of the positive square free divisors of 5400. Note: A natural number is square free if it is not the multiple of any perfect square greater than 1.
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|dw:1472005234691:dw| now try to write required divisors
i think only divisors are 2,3,5,6 which are not multiples of square numbers.
10 is also there.
How about 15
yes it is also there. I am thinking about more if any.
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30 is also there.
so for we are able to find 2,3,5,6,10,15,30
I think I got it now. I figured out a formula. The prime factorization consists of 2,3, and 5. (2+1) * (3+1) * (5+1) = 3*4*6=72. I think thats the answer? Thanks for the help!
Nice, it seems we have to find the sum of all the divisors of \(2\times 3\times 5\)
72 looks good !
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Thanks again
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