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Mathematics 7 Online
OpenStudy (tylerballardwildcat):

Find the number of permutations of the first 13 letter of the alphabet taking 4 letters at a time.

OpenStudy (niksbhalla14mar):

again, similar to last one, 13P4. or going by logic... For First position we have 13 options. For second position we have 12 options. For 3rd position we have 11 options. For 4th position we have 10 options. So Total Ways are 13x12x11x10

OpenStudy (tylerballardwildcat):

17,160

OpenStudy (tylerballardwildcat):

thanks

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