Question

2 people are approaching a fountain. Both walk at 2m/s and are 300m away from the fountain. They are facing each other. Person A leaves at 8am and person 2 leaves at 8:02am. Find the distance between them at any time t after 8am

Answer 1

@Nnesha @Anaise help pls

Answer 2

In 2 seconds, Person A must have walked 4m and so the difference between them would be (600-4=596m). Now they are walking in opposite direction. So their relative speed would be 2+2=4m/sec
Distance between them after 1 sec would be 596 - 4x1
Distance between them after 2 sec would be 596 - 4x2
Distance between them after 3 sec would be 596 - 4x3
So Now, can you guess the distance beetween them after t sec ?