Question

Hallo! Need help with a question :) (I attached them below)

Answer 1

So we have the expression \(\large a_n = 2a_{n-1} +3\)

And are given \(\large a_1 = 2\)

What i we want to find \(\large a_2\)???

Well to find \(\large a_2\) ...lets plug in \(\large n=2\)

\[\large a_2 = 2a_{2-1} + 3\]
\[\large a_2 = 2a_{1} + 3\]

So this says...to find \(\large a_2\) we simply plug in \(\large a_1\) here

\[\large a_2 = 2(2) + 3\]
\[\large a_2 = 7\]

And you just continue on from there to solve for \(\large a_3 , a_4\) etc....