Question

algebra 2

Answer 1

AVIATION:2 planes left an airport at noon.one flew east one flew west at twice the speed.After 3 hours the planes were 2700 mi apart. how fast was each plane flying

Answer 2

@CandyCove

Answer 3

x = speed of slower plane flying east
y = speed of faster plane flying west

the faster plane few twice as fast, so y = 2*x

Answer 4

use the formula

distance = rate*time

"rate" is another word for "speed"

Answer 5

idk how to do it

Answer 6

plane flying east

distance = rate*time
d = x*3
d = 3x

---------------------

plane flying west

distance = rate*time
d = y*3
d = 3*y
d = 3*(2x) ... replace y with 2x
d = 6x

Answer 7

the two distances must add to 2700, so

3x+6x = 2700

Answer 8

thx jim

Answer 9

no problem