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Mathematics 8 Online
OpenStudy (allen27):

algebra 2

OpenStudy (allen27):

the length of a rectangle is 3 cm greater than its width. the perimeter is 24 cm. what are the dimensions of the rectangle

OpenStudy (allen27):

@jim_thompson5910

jimthompson5910 (jim_thompson5910):

"the length of a rectangle is 3 cm greater than its width" means L = W+3

jimthompson5910 (jim_thompson5910):

perimeter of a rectangle P = 2*(L+W) P = 2*(W+3+W) ... replace L with W+3 24 = 2*(W+3+W) ... replace P with 24 solve for W

OpenStudy (allen27):

so its 24=2w + 6 +2w?

jimthompson5910 (jim_thompson5910):

keep going

OpenStudy (allen27):

i dont understand

jimthompson5910 (jim_thompson5910):

where are you stuck?

OpenStudy (allen27):

24 = 2*(W+3+W) ... replace P with 24 solve for W

jimthompson5910 (jim_thompson5910):

So you're not sure how I was able to replace P with 24?

OpenStudy (allen27):

ohhh my bad

jimthompson5910 (jim_thompson5910):

I did that because the given perimeter is 24

OpenStudy (allen27):

but i still dont know how to solve it sry

jimthompson5910 (jim_thompson5910):

well you distributed properly when you wrote 24=2w + 6 +2w

jimthompson5910 (jim_thompson5910):

the next step is to combine like terms on the right side

jimthompson5910 (jim_thompson5910):

what would 2w+6+2w simplify to?

OpenStudy (allen27):

4w+6

jimthompson5910 (jim_thompson5910):

yes

jimthompson5910 (jim_thompson5910):

so 4w+6 = 24

jimthompson5910 (jim_thompson5910):

do you see how to proceed from here?

OpenStudy (allen27):

yes

OpenStudy (allen27):

thx

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