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OpenStudy (allen27):
algebra 2
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OpenStudy (allen27):
the length of a rectangle is 3 cm greater than its width. the perimeter is 24 cm. what are the dimensions of the rectangle
OpenStudy (allen27):
@jim_thompson5910
jimthompson5910 (jim_thompson5910):
"the length of a rectangle is 3 cm greater than its width" means
L = W+3
jimthompson5910 (jim_thompson5910):
perimeter of a rectangle
P = 2*(L+W)
P = 2*(W+3+W) ... replace L with W+3
24 = 2*(W+3+W) ... replace P with 24
solve for W
OpenStudy (allen27):
so its 24=2w + 6 +2w?
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jimthompson5910 (jim_thompson5910):
keep going
OpenStudy (allen27):
i dont understand
jimthompson5910 (jim_thompson5910):
where are you stuck?
OpenStudy (allen27):
24 = 2*(W+3+W) ... replace P with 24
solve for W
jimthompson5910 (jim_thompson5910):
So you're not sure how I was able to replace P with 24?
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OpenStudy (allen27):
ohhh my bad
jimthompson5910 (jim_thompson5910):
I did that because the given perimeter is 24
OpenStudy (allen27):
but i still dont know how to solve it sry
jimthompson5910 (jim_thompson5910):
well you distributed properly when you wrote 24=2w + 6 +2w
jimthompson5910 (jim_thompson5910):
the next step is to combine like terms on the right side
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jimthompson5910 (jim_thompson5910):
what would 2w+6+2w simplify to?
OpenStudy (allen27):
4w+6
jimthompson5910 (jim_thompson5910):
yes
jimthompson5910 (jim_thompson5910):
so 4w+6 = 24
jimthompson5910 (jim_thompson5910):
do you see how to proceed from here?
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OpenStudy (allen27):
yes
OpenStudy (allen27):
thx
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