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If f(x)=(3x+1)/5, then find: A.) f(3) and f(-7) - I got f(3)=2 and f(-7)=-4 is this right? B.the value of k if f(k)=8 C. Find a value of k such that f(k)=k
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\[f(x) = (3x+1) \over 5\]
A is good now B
let the RHS =8, solve for x
I'm confused about where k came into play
just letter, ignore it.
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f(x) = (3x+1)/5 f(k)=(3k+1)/5 same!!
it is not important
Okay so it makes no difference then??
So b is f(8)=5?
No, I said , let the right hand side =8, solve for x
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it meant (3x+1)/5=8
now, solve for x
So x=13??
Part C: \[f(k)=\frac{ 3k+1 }{ 5}=k\] \[k=\frac{ 1 }{ 2}\] (answer)
Thank you guys!!
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