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(8a^6b^3/2)^2/3
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\[(8a^{6}*b^{\frac{ 2 }{ 3 }})^{\frac{ 2 }{ 3 }}\]
any ideas on how to start?
@kbenson1
I thought you start by multiplying everything in the ( ) by 2/3
yep
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can you show your work
Laws of indices: \[(a^b)^c = a ^{bc}\] \[(ab)^c = a^c \times b^c\] Does this help?
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