Question

E

Answer 1

@agent0smith @triciaal

Answer 2

@steve816

Answer 3

idk

Answer 4

You still there?

Answer 5

hint
\[-1 = cis~\pi = \cos \pi + i \sin \pi\]

Answer 6

More fully:
remember the modulus for z = a+ ib is
\[|z| = \sqrt{a^2 + b^2} ~ and ~ Arg(z) = \pi - \tan^{-1} (\frac{ b }{ a }) ~ for~quadrant~ II\]