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Help me understand this por favor!
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\[f(x)=\frac{ \left| x \right| }{ x^2+a },f(-x)=\frac{ \left| -x \right| }{ (-x)^2+a }=\frac{ \left| x \right| }{ x^2+a }=f(x)\] f(x) is even' if f(-x)=-f(x),then f(x) is odd.
thank you so much! @sshayer
so for the next one would it be: -x(-x^4 +7) and then when you distribute you get x^2 +7 which is even?
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@sshayer
\[f(-x)=-x \left\{ \left( -x \right)^4+7 \right\}=-x(x^4+7)=-f(x)\]
which is odd.
@jim_thompson5910
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I'm really confused
which part are you on @pflori1234_pop ?
the second one
@jim_thompson5910
ok one moment
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what did you get for `g(-x)` ?
even
@jim_thompson5910
what expression did you get?
-0
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