Question

Can someone check my work? Interval notation? Will Post below.

Answer 1

Um, domain is the value that x can take. In question 8, x can take any value.

Answer 2

Can you explain what I should have done instead? and how do you know it can take any value? I really don't understand. @admit1235813

Answer 3

\[h(x)=x^2-9,- \infty <x< \infty\]

Answer 4

\[z(x)=\frac{ 4 }{ x^2+9 },x^2 \geq 0 ~for~ all ~x\]
z(x) is defined for all x
so domain is all real numbers

Answer 5

I'm so confused. I really don't understand this concept.

Answer 6

\[x^2+9 \geq9 \neq 0\]
so denominator is not zero for any value of x
domain is all real numbers or\[-\infty <x<\infty \]

Answer 7

For part a, domain is all real numbers
@sshayer is talking about part b

Answer 8

*I meant the question of left and right