Question

The work of a student to solve a set of equations is shown:
Equation A: y = 15 – 2z
Equation B: 3y = 3 – 4z
Step 1:
 –3(y) =  
–3(15 – 2z)
     [Equation A is multiplied by –3.]

3y =  
3 – 4z
     [Equation B]

Step 2:
–3y =  
15 – 2z
     [Equation A in Step 1 is simplified.]

3y =  
3 – 4z
     [Equation B]

Step 3:
0 =  
18 – 6z
     [Equations in Step 2 are added.]

Step 4:
6z =  
18


Step 5:
z =  
3



In which step did the student first make an error? (5 points)
 
 

Step 4

Step 3

Step 2

Step 1

Answer 1

someone pls help i have 20 minutes left, i know its alot but could u give me the answer and describe why pls

Answer 2

@pooja195

Answer 3

@sammixboo @zepdrix

Answer 4

@pooja195 @pooja195

Answer 5

pls help, someone

Answer 6

step 2. He multiplied y by -3 but did not do so for the Right Hand Side of the equation.

Answer 7

Ok, ty so much.