What is the f of x over the g of x when f(x) = 6x3 − 19x2 + 16x − 4 and g(x) = x − 2?

6x2 − 7x + 2
3x2 − 9x + 8
6x2 − 7x + 2 − 8 over the quantity of x minus 2
3x2 − 9x + 8 − 8 over the quantity of x minus 2

Question

What is the f of x over the g of x when f(x) = 6x3 − 19x2 + 16x − 4 and g(x) = x − 2?

 6x2 − 7x + 2
 3x2 − 9x + 8
 6x2 − 7x + 2 − 8 over the quantity of x minus 2
 3x2 − 9x + 8 − 8 over the quantity of x minus 2

aabomosalam1998 · Answer

http://www.sosmath.com/algebra/factor/fac01/fac01.html Hope this helps :)

mathmale · Answer

I'd suggest you write out the actual fraction f(x) / g(x).

You may have to use long division to divide function g(x) into function f(x).  It's important that you share your own work so that others can give you meaningful feedback on it.