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If x^2-y^2=12 and x-y=4, what is the value o x^2+2xy+y^2?
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hint: factorise x^2 - y^2 and x^2 + 2xy + y^2 separately
So (x+y)(x-y)=12
(x+y)(x-y)=12.....(1) (x-y)=4....(2) use equation 1 & 2 to find (x+y), then \(x^2+2xy+y^2=(x+y)^2=?\)
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