Question

( 2^8 * 3^-5 * 6^0 ) * { 3^-2 / 2^3 } * 2^28 can somebody help me

Answer 1

Lol tho this belongs to math section, and they would help there better... anyways @khaleema So your question should look like this I belive:
\((2^8 *3^{-5} * 6^0)\) * \(\{\frac{ 3^{-2} }{2^3}\}*2^{28}\)