help
/-4b-8/+/-1-b^2/+b^3 b=-2
Well, if b = -2 then you just want to plug in the -2 where b is. THen you solve
but what about the absolute value im lost
This is absolute value equation?
yes / / are the absolute value signs
Hmm.. what grade are you? I have studied equation in my high school. But I'm afraid this is not like that.
10th
but this is 11th grade math
Here we go |(−4)*(−2)−8|+|−1−(−2)^2|+(−2)^3 =0+5+(-8) =−3
It's 10 grade in my country :D
do you mind one more
solve the equation check for extraneous solutions 9/9-8x/=2x+3
can you help @Kevin
so, we must find x value?
yes
and check for extraneous solutions whatever that means
Ok wait for a few minute, I'm thirsty :D
lol ok
are you almost done lol i have one more assignment to do
I know the answer, I just try to type it in formal writing :D
if you want just the answer, i can give it :)
i have to show my work
3 minutes :D
ok
9|9-8x| = |81 - 72x| (81-72x)= 0 x = 9/8 for x >= 0 -(81-7x)=0 x = 9/8 for x < 0
|81 - 72x| = 2x + 3 i (81 - 72x) = 2x + 3 -74x = -78 x = 39/37 ii -(81 - 72x) = 2x + 3 -81 + 72x = 2x + 3 70x = 84 x = 6/5
So the answer is x = 39/37 or x = 6/5
That's how my teacher teach me in my country, I dunno in your country :/
But although our teacher method is different, the answer will be same
where are you from
So what's your other question. I'm going to go sleep after that :D
Indonesia
wow lol and this was the last one lol
Lol.., so this has been done right?
I'm going to go sleep now, if you have any question you can pm me :D I study at computer science now.
is there an extraneous solution
did you mean this (81-72x)= 0 x = 9/8 for x >= 0 -(81-7x)=0 x = 9/8 for x < 0 I dunno what is extraneous solution since it's using english language. lol
well I'm understand what you mean
since we can plug both of 39/37 and 6/5 in so there are no extraneous solution
you can check 39/37 and 6/5 to the original equation. They will match.
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