Question

Ray EC bisects angle BED , m angle AEB =11x-12 and m angle CED= 4x+1. Find m angle AEC. Picture is below!

Answer 1

EC bisect angle BED
m<AEB=11x-12
m<CED=4x+1

find m<AEC

m<AEB +m<CED+m<BEC =180
11x-12 +4x+1 +4x+1 =180
19x -10 =180
19x = 190

x = 190/19

x = 10

m<CED=m<BEC=4*10+1=41 degrees
m<AEB=11x-12 =11*10-12=110-12 =98 degrees

m<AEC=m<AEB +m<BEC =98 +41 =139 degrees

m<AEC = 139 degrees

hope helped