Question

PLEASE HELP

Answer 1

what do u think?

Answer 2

lets see

Answer 3

crap i cant do, thats hard

Answer 4

is this your question?
\[\sqrt{4(y)}-\sqrt[3]{z^3+x}\sqrt{36}\]

Answer 5

ok so this is a substitution again
\[\sqrt{4(4)}-(\sqrt[3]{(-2)^3(-1)})(6)\]

Answer 6

just of of curiosity is the question possibly
\[\sqrt{4(y)}-\sqrt[3]{z^3}+x \sqrt{36}\]

Answer 7

if so the answers are a lot easier to deal with

Answer 8

well its kind of important lol

Answer 9

\[\sqrt{4(4)}-\sqrt[3]{(-2)^3}+(-1)(\sqrt{36})\] so this is where were at

Answer 10

now I will simplify it a bit more
\[\sqrt{16}-\sqrt[3]{-8}-\sqrt{36}\]

Answer 11

Do you know how to simplify it from here?

Answer 12

Ok what is the square root of 16.

Answer 13

ok so lets rewrite it
\[4-\sqrt[3]{-8}-\sqrt{36}\]

Answer 14

what is the cube root of -8? (what goes into -8 three times)

Answer 15

what is \[-2\times-2\times-2=\]

Answer 16

so the cube root of -8 is -2

Answer 17

\[4-(-2)-\sqrt{36}\]
so what is the square root of 36?

Answer 18

nice so
\[4-(-2)-6=\]

Answer 19

nice good job :)