Question

precal help needed: see attachment!

Answer 1

let f(x)=y.

Answer 2

okay, following..

Answer 3

then y=(x-2)^(1/3)+8

Answer 4

implies (y-8)=(x-2)^(1/3)

Answer 5

cube both sides to get x-2=(y-8)^3

Answer 6

then x=2+(y-8)^3

Answer 7

f inverse x will be given by replacing y by x in the rhs

Answer 8

The aim is to write x in terms of y and then the rhs will give the inverse

Answer 9

so now its \[f^{-1}(x)=(8-x)^3+2\]

Answer 10

no,,, x-8

Answer 11

f inverse x= (x-8)^3+2

Answer 12

that's what i put

Answer 13

but you put 8-x instead of x-8

Answer 14

\[f^{-1}(x)=(x-8)^3+2\]
ohh okay, my bad. So now its

Answer 15

correct.:)