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if y=3 when x=9 find x when y=1 & if y=2 when x=0.5 find y when x=3
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hi
\[\frac{ 9 }{ 3 }=\frac{ x }{ 1 }\] Now cross multiply and solve for x.
Do you know how to cross multiply?
Yes but I also need the answer for the second problem
Alright, well what's the answer to the first problem?
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x=3 ??? lol
Correct! Here's the second problem. \[\frac{ .5 }{ 2 }=\frac{ 3 }{ y }\]
and do the same for the previous problem?
Yes!
y=1.2 ? I calculated and that's the answer I got
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I think y is 12..
either one will work lol
\[\frac{ 6 }{ .5 }=12\]
Oh okay, thanks!
Of course! Need anymore help?
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Can you also help me with y=2 when x=1 and y=-3 when x=1
So usually it's \[\frac{ x }{ y }\] and so how about you try this problem?
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